50=50+2t-0.0625t^2

Solution for 50=50+2t-0.0625t^2 equation:

50=50+2t-0.0625t^2

We move all terms to the left:

50-(50+2t-0.0625t^2)=0

We get rid of parentheses

0.0625t^2-2t-50+50=0

We add all the numbers together, and all the variables

0.0625t^2-2t=0

a = 0.0625; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·0.0625·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*0.0625}=\frac{0}{0.125}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*0.0625}=\frac{4}{0.125}
=32
$